Cálculo en Variedades – Michael – Download as PDF File .pdf), Text File .txt) or read online. Cálculo en Variedades – Michael Spivak – Download as PDF File .pdf) or read online. Title, Cálculo en variedades. Author, Michael Spivak. Edition, illustrated, reprint. Publisher, Reverte, ISBN, ,

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Let be an orthogonal basis of. Further, maps each to falculo scalar multiple of itself; so is a map of the type in part b. Show that is norm preserving if and only if is inner product preserving.

### Spivak – Calculus – of – Manifolds – Solutions (2) – Soluções do Livro do Spivak

So since the integrand is always non-negative it must be that its discriminant is negative. If there is a basis of and numbers such thatprove that is angle preserving if and only if all are equal.

Parte spiak de Since is a linear map of a finite dimensional vector space into itself, variedads follows that is also onto. For the converse, suppose that is angle preserving. The first assertion is the triangle inequality. Prove that if is norm preserving, then is angle preserving.

So, this condition suffices to make be angle preserving. Let be norm preserving. The angle preserving are precisely those which can be expressed in the form where U is angle preserving of the kind in part bV is norm preserving, and the operation is functional composition. Then the inequality holds true in an open neighborhood of since and are. I claim that equality holds precisely when one vector is a non-positive multiple of the other.

Trabalho do Professor Shing Tung Yau. Wpivak, any of this form is angle preserving as the composition of two angle preserving linear transformations is vaiedades preserving. Then impliesi.

If and in are both non-zero, then the angle between anddenotedis defined to be which makes sense by Varkedades 2. Note, however, that the equality condition does not follow from a. So T is Equality holds precisely when one is a nonnegative multiple of the other. A linear transformation is called norm preserving if1. On the other hand, ifthen the result follows The inequality follows from Theorem Geometrically, if, and are the vertices of a triangle, then the inequality says that the length of a side is no larger than the sum of the lengths of the other two sides.

If for some realthen substituting shows ej the inequality is equivalent to and clearly equality holds if a is non. No, you calcuol, for example, vary at discrete points without changing the values of the integrals. Further, is norm preserving since. If and are continuous, then the assertion is true. This completes the characterization. If for some realthen substituting back into the equality shows that must be non-positive or must be 0.

The case where is treated similarly.

The linear transformation is angle preserving if is and for1. The transformation is by Cramer’s Rule because the determinant of its matrix is 1.

## Calculo En Variedades/ Calculus of Variations

This is a consequence of the analogous assertion of the next problem. Further, giventhere is a withand so.

To correct the situation, add the condition that the be pairwise orthogonal, because all the cross terms are zero. Similarly, if is norm preserving, then the polarization identity together with the linearity of T give:. Then part a gives the inequality of Theorem 2.

## Michael David Spivak

In fact, suppose that for eachthere is an with. In particular, has an inverse. Define to be the linear transformation such that is angle preserving, the are also pairwise orthogonal.